rottenchops
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- Jun 26, 2008
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Hi, everyone. First, my apologies if this has been answered already and I've failed to find it...
I've got a Mark IV combo to which I would like to connect an external 8-ohm cabinet, while keeping the internal speaker connected (to the 8-ohm output).
The external cabinet in question has 2 jacks which are wired in parallel.
My question boils down to: what would be the best way to make use of this cabinet (remember, I'd like to keep the internal speaker connected if at all possible)?
Here are 2 scenarios that come to mind:
1. Connect the cabinet to one of the 4-ohm outputs and deal with the high-side impedance mismatch.
2. Not sure if this is possible, or just stupid - connect both 4-ohm outputs on the amp to both jacks on the cabinet. Would this in effect present a 4-ohm load to the amp?
From what I gather from the Mark IV manual, the two 4-ohm outputs on the amp are internally wired in parallel but I'm not clear on how the 8-ohm output (for the internal speaker) is wired in relation, if at all. For example, if I connect an 8-ohm cab to each of the 4-ohm outputs, as recommended by the manual, can I leave the internal speaker connected to the 8-ohm output and still be perfectly matched?
I hope I'm making sense... Thanks in advance!
I've got a Mark IV combo to which I would like to connect an external 8-ohm cabinet, while keeping the internal speaker connected (to the 8-ohm output).
The external cabinet in question has 2 jacks which are wired in parallel.
My question boils down to: what would be the best way to make use of this cabinet (remember, I'd like to keep the internal speaker connected if at all possible)?
Here are 2 scenarios that come to mind:
1. Connect the cabinet to one of the 4-ohm outputs and deal with the high-side impedance mismatch.
2. Not sure if this is possible, or just stupid - connect both 4-ohm outputs on the amp to both jacks on the cabinet. Would this in effect present a 4-ohm load to the amp?
From what I gather from the Mark IV manual, the two 4-ohm outputs on the amp are internally wired in parallel but I'm not clear on how the 8-ohm output (for the internal speaker) is wired in relation, if at all. For example, if I connect an 8-ohm cab to each of the 4-ohm outputs, as recommended by the manual, can I leave the internal speaker connected to the 8-ohm output and still be perfectly matched?
I hope I'm making sense... Thanks in advance!