over paz vega
i don´t know what are you trying to mean, so a little explanation about the bias:
all electronics components needs a voltage or current to see on its inputs to starts to drive the signal.
so we need to put a dc voltage at the input to starts the signal flows. Tubes works with a current flow of electrons from cathode to anode, that electrons are generated and force to jump thru the vacumm environment by the filaments.
So for example in triode tubes we have three parts, an anode, a cathode and a grid. The grid is the input and cathode and anode are the amplified output in voltage or current depending if it is a common cathode or common anode design.
We put the dc main power supply on the anode and we need that grid and cathode be very lower voltage compared with the anode. When we create a great potential between two plates, it creates an electron flows that try to minimize the potential looking for equipotential surfaces.
For that reasons and due the tubes needs great potentials to create that little currents ( very low efficiency ) we polarizate the anode with greats positive voltage from 150 to 250 volts and we polarizate the grid with negative voltages. The point of polarization of the grid is the bad-common know as bias point ( a bias point is not only the grid voltage, it is all the tube circuitry on dc voltages, anode, cathode, grid, resistors of all that components...). when you polarizate the tube you are thinking in the totally bias point of the tube, how do you want to manage, your input signal and the kind of circuit you´re implementing.
Of course solving the ecuation of the circuitry of the tube the anode is the highest positive voltage, the grid is usually negative voltage and the cathode is very lower than grid voltage, we need that voltages to create the electrons flow.
After this little explainment we must to know that grid voltages are negative.
In conclusion, we need to polarizate the grid with an upper dc voltage than the voltage threshold ( the voltage that starts the tube to create an inside current ) this voltage is applied on the grid and helps the tube to flows electrons from cathode thru anode. If we don´t fix that voltage the input ac signal will fixed it, the problem is that with very lower input signals the tube will not flows electrons. So with high input signal voltages we will get the tube polarizate with an ac signal, but with lower signals it will not be polarizate. think in a sinusoidal signal it has maximuns on the summit if the waverforms and minimuns when the signal passes by zero. Near the zero point it will create a square waveform due the tube doesn´t has enough voltage to be polarizate, in the spectrum domain a square wave is translate into high frecuency odd harmonics.
We polarizate the tube with a bias point to fix it in a work zone and to avoid that distortion by zero issue, so if we put a lower than threshold voltage we will get the issue i was quoting.
:roll: